Question

kolejny przykład

różni się od poprzedniego tylko jedną potęgą

Answer 1

x²+y²          x+y

--------   -   ---------   +   1  =                                              Z: x+y ≠ 0

x²-y²          2x-2y                                                                 x ≠ -y

                                                                                          x-y ≠ 0

                                                                                          x ≠ y

   x²+y²              x+y                                                          

------------   -   ----------   +   1  = 

(x+y)(x-y)         2(x-y)

 

 

2(x²+y²)-(x+y)²+2(x+y)(x-y)              2x²+2y²-(x²-2xy+y²)+2(x²-y²)

-----------------------------------       =    -------------------------------------   =

         2(x+y)(x-y)                                        2(x²-y²)

 

 

2x²+2y²-x²-2xy-y²+2x²-2y²           3x²-2xy-y²   

----------------------------------   =   ----------------

         2x²-2y²                              2x²-2y²

Answer 2