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zał.x≠5 i x≠-5
a) 5÷ (x²-25) - (x+3) ÷ (5-x) + 1=
5/ (x²-25) - (x+3) /(5-x) + 1=
5/ (x²-25) - (x+3) (x+5) /-(x-5)(x+5) + 1(x²-25)/(x²-25)=
[ 5+ x²+3x+5x+1 +x²-25]/(x²-25)=[ 6+ 2x²+8x-25]/(x²-25)=
[ 2x²+8x-19]/(x²-25)