wykaż że jeśli x+y=-6 i x^2+y^2=27 to x*y=4,5
x + y = -6
x² + y² = 27
x+y = -6 | ()²
x² + 2xy + y² = 36
---------------------- <-- odejmuję stronami
2xy = 9 |:2
xy = 4,5 c.k.d
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Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
x² + y² = 27 x² + y² = (x + y)² - 2xy
(x + y)² - 2xy = 27
(-6)² - 2xy = 27
36 - 2xy = 27
-2xy = 27 - 36
-2xy = - 9
xy = 4,5 --- odpowiedx
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x + y = -6
x² + y² = 27
x+y = -6 | ()²
x² + 2xy + y² = 36
x² + 2xy + y² = 36
x² + y² = 27
---------------------- <-- odejmuję stronami
2xy = 9 |:2
xy = 4,5 c.k.d
----------------------------------------------------------------------------------------------------
Litterarum radices amarae sunt, fructus iucundiores
Pozdrawiam :)
x + y = -6
x² + y² = 27 x² + y² = (x + y)² - 2xy
(x + y)² - 2xy = 27
(-6)² - 2xy = 27
36 - 2xy = 27
-2xy = 27 - 36
-2xy = - 9
xy = 4,5 --- odpowiedx