Wykaż, że: 9+2√14 pod pierwiastkiem = √2+√7
√[9+2√14]=√2+√7/²
9+2√14=(√2+√7)²
9+2√14=√2²+2√(2×7)+√7²
9+2√14=2+2√14+7
9+2√14=9+2√14
L=P
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√[9+2√14]=√2+√7/²
9+2√14=(√2+√7)²
9+2√14=√2²+2√(2×7)+√7²
9+2√14=2+2√14+7
9+2√14=9+2√14
L=P