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sin²α=1- cos²α
sin²α=1-(2/3) ²
sin²α=1-4/9
sin²α=5/9
sinα=√(5/9)=√5/3
tgα=sinα/cosα
tgα=(√5/3)/(2/3)=√5/2
ctgα=cosα/sinα
ctgα=(2/3)/(√5/3)=2/√5=(po uwymiernieniu) (2√5)/5