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(a b)2+2(a+b)(a-b)-3(a+b)2=2ab+2(a²-b²)-6(a+b)=2ab+2a²-2b²-6a-6b=
2(ab+a²+b²-3a-b)=2[a(b+a-3)+b(b-1)]
a=4, b=-1
2[a(b+a-3)+b(b-1)]
2[4(-1+4-3)-1(-1-1)]=2(4*0)-1*-2)=2(0+2)=2*2=4