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z pitagorasa:
h₁=√5²-4²=√25-16=√9=3cm
pole Δ=½ah=½×8×3=12cm²
pole=½×5×h₂
12=2,5h₂
h₂=12:2,5
h₂=4,8cm
k=⅔
skala podobieństwa pól=k²=(⅔)²=⁴/₉
x=pole Δ podobnego
x:12=⁴/₉
x=12×4:9
x=5⅓cm²