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a=10/√2
a=10√2/2
a=5√2
b)a√2=5√2
a=5
c)a√2=3√6
a=3√6/√2
a=3√3
a)10cm b)5√2 c) 3√6
oblicz długosc ramion kazdego z tych trójkatów
a)x²+x²=10
2x²=10
x²=5
x=√5
b)2x²=5√2
x²=5√2/2
x=2√5/√2=√10
c)2x²=3√6/2
x=6√3/√2=3√6
a/ a√2 = 10 /√2
a = 10/√2 (licznik i mianownik razy √2)
a= 5√2
b/ a√2 = 5√2 /√2
a= 5
c/ a√2 = 3√6 / √2
a = 3√6/ √2
a = 3√12 / 2
a = 3√3