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obw=5π /obw kola/
α=60°
OBL
a+b+2c
ROZWIZANIE
πa=5π /a jest srednica/
a=5
jak widac z rusunku:
c=b=a/2=2,5
a+b+2c=5+2,5+5=12,5
ODP
Obwod trapezu wynosi 12,5cm
pozdrawiam
Hans