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co = 128 J / (kg * K)
Δt0 = 20st
m0 = 2kg
cm = 386 J / (kg * K)
Δtm = 5st
mm = 4kg
Qo = co * mo * Δto = 128 * 2 * 20 = 5120 J
Qm = cm * mm * Δtm = 386 * 4 * 5 = 7720J
Qm > Qo => więcej energii należy dostarczyć do podgrzania miedzi