W koło o polu 6,25π cm kwadratowych wpisano czworokąt foremny. Oblicz pole tego czworokata.
P=πr²
6,25π=πr²
r=2,5[cm]
r=1/2d
d=5[cm]
P=1/2d²
P=12,5[cm²]
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P=πr²
6,25π=πr²
r=2,5[cm]
r=1/2d
d=5[cm]
P=1/2d²
P=12,5[cm²]