W jakiej objętości amoniaku znajduje się 6g wodoru? Oblicz.
22,4dm3 NH3-------3g wodoru
xg NH3---------------6g wodoru
x = 44,8dm3 NH3
NH₃
M= 14g/mol + 3*1g/mol=17g/mol
masa wodoru w 1 molu amoniaku: 3g
3g wodoru --- 1 mol amoniaku
6g wodoru ----- x
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22,4dm3 NH3-------3g wodoru
xg NH3---------------6g wodoru
x = 44,8dm3 NH3
NH₃
M= 14g/mol + 3*1g/mol=17g/mol
masa wodoru w 1 molu amoniaku: 3g
3g wodoru --- 1 mol amoniaku
6g wodoru ----- x