Ustal wzór hydratu siarczanu (VI) sodu, w którym siarka stanowi 9,938% jego masy.
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MHydr=(142+X*18)g/mol
MS=32g/mol
%S=9,938%
więc
100%-Mhydr
%S - MS
100-142+X*18
9,938 - 32
3200=1411,196+178,884*x
1788,8=178,88*X
X=10
Na2SO4*10H2O