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Σr=0 ---- Σx = T(0.42m)xsen30 - 250N(0.25m) = 0
T = 250N(0.25m) / (0.42m)xsen30
T = 297.6N --- 3.0 x10^2N (A dos cifras significativas)
2) Aplicamos la segunda ley de Newton.
Σx=0 -- Σx = Bx - Tcos30 = 0
Bx= Tcos30 = (297.6N)xcos30 = 0.87N
Σy=0 --- Bx + Tsen30 - 250N = 0
Bx= 250N - Tsen30 = 101.2N -- 1.0 x10^2 (A dos cifras significativas)