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h Δ =a√3:2=12√3:2=6√3cm
⅓h=⅓×6√3=2√3cm
⅔h=⅔×6√3=4√3cm
a]pole opisanego koła=πr²=π×(4√3)²=48πcm²
obwód opisanego=2πr=2π×4√3=8√3πcm
b]pole wpisanego koła=πr²=π×(2√3)²=12πcm²
obwód wpisanego koła=2πr=2π×2√3=4√3πcm
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