Question

Tolongg di bantu yahh hehe

Answer 1

X² + (p+1)x + 2 = 0; akar2 x1 dan x2

x² + (p-1)x + 6 = 0; akar2 x2 dan x3

hubungan x1,x2,x3:
x1.x2 = 2 ; x2.x3 = 6
x2 = 2/x1
maka: x3 = 3.x1

x1+x2 = -p-1
x2+x3 = -p+1 ← subtitusi x3 = 3x1, kemudian eliminasi x2:

  x1+x2 = -p-1
3x1+x2 = -p+1 (-)
     -2x1 = -2
        x1 = 2; maka x2 = 1 dan x3 = 3

x1+x2+x3 = 2+1+3
                 = 6................opsi E