Question

29PK tolong yah hehe

Answer 1

Akar2 m dan n
m.n = c/a = 2/1 = 2
m + n = -b / a = -(-6)/1 = 6
1/m + 1/n = (m+n) / m.n = 6 / 2 = 3
maka akar2nya
(1/m + 1/n)^(m.n) = (3)^2 = 9 ----> x1
(m.n)^(1/m + 1/n) = (2)^3 = 8 --->x2
persamaan kuadrat baru
x² - (x1+x2)x + x1.x2 = 0
x² - (9+8)x + 9.8 = 0
x² - 17x + 72 = 0
jawab a