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Cari hubungan x1,x2, dan b:
2x1+x2 = 5
x1+b = 5
x1 = 5-b ; x2 = 2b-5
Cari nilai b:
x1.x2 = b-1
(5-b)(2b-5) = b-1
10b-25-2b²+5b = b-1
2b²-14b+24 = 0
b²-7b+12 = 0
(b-3)(b-4) = 0
b = 3 atau b = 4............opsi D