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(x²+ax)(m-2) = (bx-2)(m+2)
mx²+max-2x²-2ax = mbx-2m+2bx-4
mx²-2x²+max-mbx-2ax-2bx+2m+4 = 0
(m-2)x² + (ma-mb-2a-2b)x + 2m + 4 = 0
berlawanan x1 = -x2 ---> x1 + x2 = 0
x1 + x2 = - b / a karena = 0 berarti b = 0
ma - mb - 2a - 2b = 0
ma - mb = 2a + 2b
m(a - b) = 2(a + b)
m = 2(a + b) / (a - b)
jawab = b