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CF4 ⇒ BO.C = 4+ dan BO.F = 1-
CHCl3 ⇒ BO.C = 2+ , BO.H = 1+ dan BO.Cl = 1-
O2F2 ⇒ BO.O = 1+ dan BO.F = 1-
KO2 ⇒ BO.K = 1+ dan BO.O = -1/2
CaH2 ⇒ BO.Ca = 2+ dan BO.H = 1-
BaO2 ⇒ BO.Ba = 2+ dan BO.O = 1-
Fe2S3 ⇒ BO.Fe = 3+ dan BO.S = 2-
CuO ⇒ BO.Cu = 2+ dan BO.O = 2-
N2O4 ⇒ BO.N = 4+ dan BO.O = 2-
CaO ⇒ BO.Ca = 2+ dan BO.O = 2-
SnO ⇒ BO.Sn = 2+ dan BO.O = 2-