Question

TOLONG DIBANTU. PAKE CARANYA YAA. MAKASIH SEBELUMNYA

Answer 1

Nomor 1

massa awal = 21 kg
massa sisa = 18,37 kg
massa keluar = 21 - 18,37 = 2,63 kg

Nomor 2
Volume tetesan = 4/3 π R³ = 4/3 π (3*10⁻⁴)³ = 1,13*10⁻¹⁰ m³
massa tetesan = ρ V = 13.600 * 1,13*10⁻¹⁰ = 1,54*10⁻⁶ kg
jumlah mol = m / Mr = 1,54*10⁻⁶ / 200 = 7,69*10⁻⁹ kmol
jumlah partikel = n * 6,02*10²⁶ = 7,69*10⁻⁹ * 6,02*10²⁶ = 4,63*10¹⁸ atom raksa

Nomor 3
Volume silinder = π R² h = π * 10² * 15 = 4712,4 cm³ = 4,7124*10⁻³ m³
Tekanan = 200 kPa = 2*10⁵ Pa
suhu = 27°C = 27 + 273 = 300 Kelvin
jumlah mol = ?
PV = nRT
2*10⁵ * 4,7124*10⁻³ = n * 8,314 * 300
n = 0,38 mol

Nomor 4
Tekanan = 2*10⁵ N/m²
Suhu = 57°C = 57+273 = 330 K
Jumlah partikel = 18,06*10²²
a) Volume = ?
PV = NkT
2*10⁵ * V = 18,06*10²² * 1,38*10⁻²³ * 330
V = 4,11*10⁻³ m³ = 4,11 liter
b) massa = ?
m = {N/(6,02*10²³)}*Mr = {(18,02*10²²)/(6,02*10²³)}*44 = 13,17 gram
m = 13,17*10⁻³ kg

Nomor 5
Mr = 44 kg/kmol
T = 77°C = 77 + 273 = 350 Kelvin
V = 0,2 * 0,7 * 0,1 = 14*10⁻³ m³
P = 2*10⁵ Pa
a) massa jenis?
PV = (m/Mr) * R * T
2*10⁵ * 14*10⁻³ = (m/44) * 8314 * 350
m = 4,23*10⁻² kg
ρ = m/V = 4,23*10⁻² / (14*10⁻³) = 3,024 kg/m³
b)  massa = ?
m = 4,23*10⁻² kg