Question

∫... Tolong berikan penjelasannya... terima kasih...

Answer 1

∫ 1/(x²-4x+13) dx
= ∫ 1/((x-2)² + 9) dx   ; subtitusi u = x-2 → du = dx
= ∫ 1/(u² + 9) du
= ∫ 1/9((u/3)² + 1) du   
= ∫ 1/9.(-tan² (u/3))
= (1/3.tan (u/3)) + C
= (1/3).tan⁻¹ ((x-2)/3) + C