Question

Hasil dari ∫cos² 2x. sin 2x dx? beserta caranya... terima kasih

Answer 1

∫cos²2x.sin2x dx

misal,
u = cos(2x)
du = -2sin(2x) dx
dx = du/(-2sin(2x))

∫cos²2x.sin2x dx = ∫u².sin(2x) du/(-2sin(2x))
= ∫-(1/2)u² du
= -(1/2)∫u² du
= -(1/2)(1/3) u³ + C
= -1/6 u³ + C

Answer 2

Jawaban di lampiran...