Question

Jawaban Integral 3 akar 3x = ?

Answer 1

∫ 3√(3x)  dx = ∫ (3√3) (√x) dx 
= ∫ 3√3 x¹/² dx
= (3√3) . (²/₃) (x ³/²) + c
= (3√3)(2/3)(x√x) + c
= (2√3)(x√x) + c
= 2x√(3x) + c

cara lain
∫ 3√(3x) dx = ∫ 3.(3¹/²)(x¹/²)  dx
= 3³/² . (²/₃) . (x³/²) + c
= 3√3 . (²/₃) . (x√x) + c
= (3)(²/₃)(x) (√3)(√x) + c
= 2x √(3x) + c