Jawab:
limit trigonometri bentuk 0/0
Penjelasan dengan langkah-langkah:
lim(x-> 0) {√(1 - cos x)} / ( x) =
.
1 - cos x = 1 - ( 1 - 2 sin² 1/2 x )
1 - cos x = 2 sin² 1/2 x
= lim(x-> 0) {√(2sin² 1/2 x)} / ( x)
= lim(x->0) (√2)(sin 1/2 x ) /(x)
= (√2) ( 1/2)
= 1/2 √2
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Jawab:
limit trigonometri bentuk 0/0
Penjelasan dengan langkah-langkah:
lim(x-> 0) {√(1 - cos x)} / ( x) =
.
1 - cos x = 1 - ( 1 - 2 sin² 1/2 x )
1 - cos x = 2 sin² 1/2 x
.
lim(x-> 0) {√(1 - cos x)} / ( x) =
= lim(x-> 0) {√(2sin² 1/2 x)} / ( x)
= lim(x->0) (√2)(sin 1/2 x ) /(x)
= (√2) ( 1/2)
= 1/2 √2