to co na załączniku
a) (1 i 3/4)⁶ × (2/7)⁶ = (7/4 × 2/7)⁶ = (1/2)⁶ = 1/64
b) (0,8)⁴ : (2 i 2/3)⁴ = (8/10 × 3/8)⁴ = 0,3 ⁴ = 0,0081
c) (-6,5)³/ (-0,13)³ = (-6,5 : -0,13)³ = 50³ = 125000
d) (4 i 1/2)³ × (-2/3)³ ×(-2)³ = 6³ = 216
e) (2 i 1/2)⁴ × 0,6⁴ × (-1/15)⁴ = 0,1⁴ = 0,0001
f) 0,3⁴ × (2 i 2/3)⁴ / (-4)⁴ = 1/5 ⁴ = 1/625
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a) (1 i 3/4)⁶ × (2/7)⁶ = (7/4 × 2/7)⁶ = (1/2)⁶ = 1/64
b) (0,8)⁴ : (2 i 2/3)⁴ = (8/10 × 3/8)⁴ = 0,3 ⁴ = 0,0081
c) (-6,5)³/ (-0,13)³ = (-6,5 : -0,13)³ = 50³ = 125000
d) (4 i 1/2)³ × (-2/3)³ ×(-2)³ = 6³ = 216
e) (2 i 1/2)⁴ × 0,6⁴ × (-1/15)⁴ = 0,1⁴ = 0,0001
f) 0,3⁴ × (2 i 2/3)⁴ / (-4)⁴ = 1/5 ⁴ = 1/625