Question

To co na załączniku 24 b i c 2 i 3

Answer 1

zad. 24

b)

(x-1)²+(x+1)(2x+3)=

=x²-2x+1 + 2x²+3x+2x+3=

=3x²+3x+4

 

c)

(3x-1)(2x+2) - (x+3)[3x-1-2(x-1)]=

=6x²-2x+6x-2 - (x+3)[3x-1-2x+2]=

=6x²+4x-2-(x+3)(x+1)=

=6x²+4x-2-(x²+x+3x+3)=

=6x²+4x-2-x²-x-3x-3=

=5x²-5

 

zad.2

3x²y³z⁵-9x³y⁵z³ = 3x²y³z³(z²-3xy²)

3x²y³z⁵-9x³y⁵z³ = xyz(3xy²z⁴-9x²y³z²)

3x²y³z⁵-9x³y⁵z³ = 9z³(⅓x²y³z²-x³y⁵)

 

u²v⁴-5u⁴v² = u²v²(v²-5u²)

u²v⁴-5u⁴v² = 5uv(⅕uv³-u³v)

u²v⁴-5u⁴v² = -5v²(-⅕u²v²+u⁴)

 

zad.3

a)

[2b(b+2)]/2 = b(b+2) = b²+2b

b)

[3d(d+5)]-2d = 3d²+15d-2d = 3d²+13d

c)

[4f(3+f)] - (4f * 3)/2 = 12f+4f² - 12f = 4f²

 

mam nadzieję, że dobrze :D