Question

(z+0,3)²+(z+0,2)(0,2-z)

2(a+b/2)²-2(a/2+b)(b+a/2)

Answer 1

(z+0,3)²+(z+0,2)(0,2-z) = z² + 0,6z + 0,09 + 0,04 - z² = 0,6z + 0,13

2(a+b/2)²-2(a/2+b)(b+a/2) = 2(a² + ab + b²/4) - 2(ab/2 + a²/4 + b² + ab/2) = 2a² + 2ab + b²/2 - ab - a²/2 - 2b² - ab = 3/2a² - 3/2b²