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F2 = 13 N searah sumbu x negatif
F3 = 10 N searah sumbu y positif
F4 = 9 N searah sumbu y negatif
di tanya : R
F1x = F1 .cos
= 14 . 1
= 14
F2x = F2 .cos 180
= 13 . - 1
= - 13 N
F3x = F3 .cos 90
= 10 . 0
= 0
F4x = F4 . cos 270
= 9 . 0
= 0 N
Σ Fx = 14 + (- 13) + 0 + 0
= 1 N
F1y = F1 . sin 0
= 14 . 0
= 0 N
F2y = F2 .sin 180
= 13 . 0
= 0 N
F3y = F3 .sin 90
= 10 . 1
= 10 N
F4y = F4 .sin 270
= 9 . - 1
= - 9
Σ Fy = 0 + 0 + 10 + (- 9)
= 1
R² = (Σ Fx)² + (Σ Fy)²
R² = 1² + 1²
R² = 2
R = √2 N
arah resultan (α)
tan α =
=
= 1
α =
jadi arah pada terhadap sunbu x