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Maka,
x² - x - 12 ≤ 0
(x+3)(x-4) ≤ 0
Maka, interval:
-3 ≤ x ≤ 4
Irisan domain:
0 ≤ x ≤ 4
Untuk x < 0
x² - (-x) - 12 ≤ 0
x² + x - 12 ≤ 0
(x+4)(x-3) ≤ 0
Interval:
-4 ≤ x ≤ 3
Irisan domain:
-4 ≤ x < 0
Sehingga, dengan menggabung kedua solusi:
HP = {x | -4 ≤ x ≤ 4, x E R}