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Vair = 6x10^-4 m^3
ρair = 1000 kg/m^3
Mr H = 1 g/mol,O = 16 g/mol
Dit. N........?
penyelesaian :
-cari m :
ρ = m/V
m = ρ.V
= (1000 kg/m^3) (6x10^-4 m^3)
= 6x10^-1
= 0,6 kg ⇒ 600 gram
-cari jmlh mol H2O :
Mr H2O = (2x1 + 16 = 18 gr/mol)
n = m / Mr
= (600 gr) / (18 gr/mol)
= 33,3 mol
-maka, jumlah molekul
N = n.NA
= (33,3 mol).(6,02x10^23 molekul/mol)
= 2x10^25 molekul