Question

TALLER DE APLICACIÓN FACTORIZACIÓN

a) 6m2 + 12mn =
b) a5 – a4 + a2 =
c) 3a3x + 2a2x2 –ax3=
d) (a + 3) (a + 1) -4 (a + 1) =
e) 1 – x + 2a (1 – x) =
f) a (n + 1) –b ( n + 1) – n – 1 =
g) (x2 + 2) (a – b) + 2 (a – b) =
h) 3x (x + 2) + 2y (x + 2) =
i) 3x (m – n) – n + m =
j) (x – 2) (x – 3) + (x – 2) (x + 3) =

Answer 1

A) 6m² + 12mn = 6m(m + 2n)
b) a⁵ - a⁴ + a² = a²(a³ - a² + 1)
c) 3a³x + 2a²x² - ax³ = ax(3a² + 2ax - x²)
d) (a + 3) (a + 1) - 4(a + 1) = a² + 4a + 3 - (4a + 4) = a² + 4a + 3 - 4a - 4
     = a² -1
e) 1 - x + 2a(1 - x) = (1 + 2a) (1 - x)
f)  a(n + 1) - b(n + 1) - n - 1 = (a - b - 1) (n + 1)
g)  (x² + 2) (a - b) + 2(a - b) = x²a - x²b + 4a - 4b = x²(a - b) + 4(a - b)
= (x² + 4) (a - b)
h)  3x(x + 2) + 2y(x + 2) = (3x + 2y) (x + 2)
i)  3x(m - n) - n + m = 3x(m - n) -(n - m) = (3x - 1) (m - n)
j) (x - 2) (x - 3) + (x - 2) (x + 3) = x² -5x + 6 + x² + x - 6 = 2x² - 4x =
2x(x - 2)