Szukam pomysłu na rozwiązanie tego przykładu:
1/n(n+1)=1/n -1/(n+1)
=1/1-1/2+1/2-1/3+1/3-1/4+1/4-........-1/2012+1/2012-1/2013=
=1/1-1/2013=2013/2013-1/2013=2012/2013
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1/n(n+1)=1/n -1/(n+1)
=1/1-1/2+1/2-1/3+1/3-1/4+1/4-........-1/2012+1/2012-1/2013=
=1/1-1/2013=2013/2013-1/2013=2012/2013