Sprowadź do funkcji kanonicznej: HELP
y = 5xkwadrat - 2x +1
-y= -2xkwadrat + 3
y = 5x² - 2x + 1
y = 5(x² - 2/5x + 1/5)
y = 5[(x - 1/5)² + 4/25]
y = 5(x - 1/5)² + 4/5 ----- postać kanoniczna
-y = -2x² + 3 / *(-1)
y = 2x² - 3
y = 2(x - 0)² - 3 = 2x² - 3 ----- postać kanoniczna
y = 5x²-2x+1 - postac ogólna funkcji kwadratowej
a = 5, b = -2, c = 1
y = a(x-p)²+q - postac kanoniczna
p = -b/2a = -(-2)/10 = 2/10 = 1/5
q = -(b²-4ac)/4a = -(4-4*5*1)/20 = -(4-20)/20 = -(-16)/20 = 16/20 = 4/5
y = 5(x - 1/5)² + 4/5
=================
-y = -2x²+3
y = 2x²-3
a = 2, b = 0, c = -3
p = -b/2a = 0
q = -(b²-4ac)/4a = -[0-4*2*(-3)] = -24/8 = -3
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y = 5x² - 2x + 1
y = 5(x² - 2/5x + 1/5)
y = 5[(x - 1/5)² + 4/25]
y = 5(x - 1/5)² + 4/5 ----- postać kanoniczna
-y = -2x² + 3 / *(-1)
y = 2x² - 3
y = 2(x - 0)² - 3 = 2x² - 3 ----- postać kanoniczna
y = 5x²-2x+1 - postac ogólna funkcji kwadratowej
a = 5, b = -2, c = 1
y = a(x-p)²+q - postac kanoniczna
p = -b/2a = -(-2)/10 = 2/10 = 1/5
q = -(b²-4ac)/4a = -(4-4*5*1)/20 = -(4-20)/20 = -(-16)/20 = 16/20 = 4/5
y = 5(x - 1/5)² + 4/5
=================
-y = -2x²+3
y = 2x²-3
a = 2, b = 0, c = -3
p = -b/2a = 0
q = -(b²-4ac)/4a = -[0-4*2*(-3)] = -24/8 = -3
y = 2x²-3
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