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1) x² + 2x -3 =0 aplicando álgebra (factorización)
(x + 3 ) (x - 1) = 0
Entonces: (x+3) = 0 & (x-1) = 0
x = -3 & x= 1
2) x² -3x-4 =0
(x - 4 ) (x + 1) = 0
Entonces:
(x - 4) = 0 & (x + 1) =0
x = 4 & x= -1
3) 3x² - 4x = 0
x(3x-4) = 0
Entonces:
x = 0 & (3x-4) = 0
x= 0 & x = 4/3