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2C₂H₂ + 5O₂ ⇒ 4CO₂ + 2H₂O
Step-1 mencari ΔH
ΔH = [4.ΔHf CO₂ + 2.ΔHf H₂O] - [2.ΔHf C₂H₂]
ΔH = [4(-393) + 2(-285)] - [2(227)]
ΔH = [- 1572 - 570] - 454
ΔH = -2596 kJ/mol
Step-2 siapkan mol C₂H₂
n = massa/Mr
n = 0,52/26
n = 0,02 mol
Step-3 final
Jumlah kalor yang dibebaskan pada pembakaran 0,52 gram C₂H₂ adalah,
[mol / koefisien] x 2596 kj/mol
= [0,02 / 2] x 2596 kJ/mol
= 25,96 kJ
___ selesai___