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wiemy,że a=tgα
a) y=(2sin60)x+tg45
2sin60=tgα
tgα=2*√3/2
tgα=√3
α=60⁰
b) y=(2cos30)x+tg30
2cos30=tgα
tgα=2*√3/2
tgα=√3
α=60⁰
c) y=cos45/sin45 x +2
cos45/sin45=tgα
tgα=tg 45
tgα=1
α=45⁰