January 2019 1 23 Report
Wykaż, że dla każdego kąta ostrego α spełniona jest równość:

cos²α/sin²α * (tg²α - sin²α) = sin²α
More Questions From This User See All

Recommend Questions



Life Enjoy

" Life is not a problem to be solved but a reality to be experienced! "

Get in touch

Social

© Copyright 2013 - 2024 KUDO.TIPS - All rights reserved.