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t=10seg
Y=?
V=?
Hallar la altura osea Y:
Y=1/2gt²
Y=1/2(9.8m/seg²)*(10seg)²
Y=4.9m/seg²*100seg²
Y=490m
Hallar la velocidad:
V²=2gy
V²=2(9.8m/seg²)*490m
V²=19.6m²/seg²*490m
V²=9.604m/seg²
V=√9.604m/seg
V=3.09m/seg²