Question

Sebanyak 100ml amonium hidroksida 0,2 M (kb 2. 10^-5 ) mempunyai pH sbesar?

Answer 1

OH^- = √ Kb × M
         = √ 2 × 10^-5 × 0,2
         = 2 × 10^-3
pOH = 3 - log 2 maka pH = 11 + log 2

Answer 2

M = 0,2 M
kb = 2×10⁻⁵

[OH⁻] = 
[OH⁻] = 
[OH⁻] = 2×10⁻³

pOH = - log [OH⁻]
pOH = -log [2×10⁻³]
pOH = 3 -log 2

pH = 14-pOH
pH = 14-(3- log 2)
pH = 11 + log 2