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M = n / V = 10^-2 / 2 = 5 . 10^-3 M
[OH-] = M . valensi anion = 5 . 10^-3 . 2 = 10^-2
pOH = 2 , pH = 14-2 = 12
= 0,74 / 74 = 0,01
ca(oh)2 = n/v = 0,01 / 2 = 0,005
(oh) = 2 x 0,005 = 0,01
poh= -log (oh)
=-log 10-2
=2
ph = 14-2
=2