Question

A horizontal cable pulls a 200 kg cart along a horizontal track. The tension in the cable is 500 N. Starting from rest, how long will it take the cart to reach a speed of 8 m/s? How far will it have gone?

(Answer: 3.2 s; 12.8 m)

Answer 1

F= mxa
500N = 200 x a
a = 2,5m/s2

(vt-v0) : a = t
(8-0) : 2,5 = t
t = 3,2 s

s = v0 x t + 1/2 a t^2
s = 1/2x2,5x3,2^2
=12,8 m