#F
= ²log 3² . ³^³log 2⁴
= (2) (²log 3 ) (4/3)(³log 2)
= 2(4/3) (²log 3. ³log 2)
= 8/3 (²log 2)
= 8/3 (1)
= 8/3
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#F
= ²log 3² . ³^³log 2⁴
= (2) (²log 3 ) (4/3)(³log 2)
= 2(4/3) (²log 3. ³log 2)
= 8/3 (²log 2)
= 8/3 (1)
= 8/3