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h = 60 x 60 x 4/5 x 4/5 / 20 = 115,2 meter
v = 60 m/s
α = 53
ditanya :
h max = ?
jawab :
h = vo² sin² 53 x 1/2g
h = 60² sin² 53 x 1/20
h = 3600 x (0,8)² x 1/20
h = 115,2 m