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v = (2t - 4) i + ( 4t - 2) j
maka kecepatannya pada saat t = 1 s adalah
v = (-2) i + (2) j
untuk besar nya = akar 4 + 4 = akar 8 = 2 akar 2
r = (t² - 4t)i + (2t² - 2t)j
Dit :
v = .... ? t = 1s
Peny :
v = dr/dt
= d/dt ((t² - 4t)i + (2t² - 2t)j)
= (2t - 4) i + (4t - 2) j
substitusi t = 1s
v = (2(1) - 4) i + (4(1) - 2) j
= (2 - 4) i + (4 - 2) j
= (-2) i + (2) j
v = √(vx² + vy²)
= √((-2)² + 2²)
= √(4 + 4)
= √8
= 2√2 m/s