rozwiążcie prosze to zadanie.
8+5= 13 - bok przeciwprostokątny
5 - I bok przyprostokątny
[tex]y^{2} + x^{2} = z^{2}
5^{2} + x^{2} = 13^{2}
25 + x^{2} = 169
169 - 25 = x^{2} 144 = x^{2} / \sqrt
12 = x
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8+5= 13 - bok przeciwprostokątny
5 - I bok przyprostokątny
[tex]y^{2} + x^{2} = z^{2}
5^{2} + x^{2} = 13^{2}
25 + x^{2} = 169
169 - 25 = x^{2} 144 = x^{2} / \sqrt
12 = x