Question

Rozwiaz rownanie A) (2x-9)(x^2+2x)(x^2+4)=0

Answer 1

A)

(2x-9)(x²+2x)(x²+4) = 0

(2x-9)·x·(x+2)(x²+4) = 0

x(2x-9)(x+2)(x²+4) = 0

x = 0

lub

2x-9 = 0  /:2

x = 4,5

lub

x+2 = 0

x = -2

x²+4 > 0  (dla każdego x)

Odp. x = -2   v   x = 0   v  x = 4,5

       

Answer 2

( 2x - 9)*( x^2 + 2 x )*( x^2 + 4 ) = 0

x*( x + 2)*( 2x - 9)*( x^2 + 4) = 0

x = 0     v     x + 2 = 0     v   2x - 9  = 0;   x^2 + 4 > 0

x = 0     v     x = - 2         v  2x = 9

Odp.  x = - 2     v      x = 0      v      x = 4,5

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