October 2018 1 47 Report

Rozwiąż:

a) 7x-2 [3-4(x-2)]=8

b) 4+3(x-4)=6-2(x-3)

c) (x-3)^{2}+(x-2)(x+2)=(x-7)(2x+1)-2

d) \frac{1}{2}x + \frac{1}{3}x + \frac{1}{7}x + \frac{1}{12}x = x + \frac{25}{42}

e) x-\frac{x+3}{2} = 7

f) \frac{2-x}{5} - \frac{2x-1}{15} = 1-\frac{x+3}{3}

g) 0,03 - 0,2 (0,1+x)< 0,01

h)\frac{x-2}{3} - \frac{3-x}{6}\geq\frac{1}{3}


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