Rozwiąż:
(x-3)²+(x-1)(x+1)=3x-2
x²-6x+9+x²-1=3x-2
2x²-6x+8=3x-2
2x²-9x+10=0
Δ=(-9)²-4*2*10=81-80=1
√Δ=1
x²-6x+8 ≥ 0
Δ=(-6)²-4*1*8=36-32=4
√Δ=2
x∈(-∞<2> ∨ <4;∞)
a)
(x-3)²+(x-1)(x+1)=3x-2x²-6x+9+x²-1=3x-22x²-6x+8=3x-22x²-9x+10=0Δ=(-9)²-4*2*10=81-80=1√Δ=1
x1=(9-1)/4=8/4=2
x2=(9+1)/4=10/4=5/2b)
x²-6x+8 ≥ 0Δ=(-6)²-4*1*8=36-32=4√Δ=2
x1=(6-2)/2=4/2=2
x2=(6+2)/2=8/2=4x∈(-∞,2> u<4;+∞)
licze na naj
" Life is not a problem to be solved but a reality to be experienced! "
© Copyright 2013 - 2025 KUDO.TIPS - All rights reserved.
(x-3)²+(x-1)(x+1)=3x-2
x²-6x+9+x²-1=3x-2
2x²-6x+8=3x-2
2x²-9x+10=0
Δ=(-9)²-4*2*10=81-80=1
√Δ=1
x²-6x+8 ≥ 0
Δ=(-6)²-4*1*8=36-32=4
√Δ=2
x∈(-∞<2> ∨ <4;∞)
a)
(x-3)²+(x-1)(x+1)=3x-2
x²-6x+9+x²-1=3x-2
2x²-6x+8=3x-2
2x²-9x+10=0
Δ=(-9)²-4*2*10=81-80=1
√Δ=1
x1=(9-1)/4=8/4=2
x2=(9+1)/4=10/4=5/2
b)
x²-6x+8 ≥ 0
Δ=(-6)²-4*1*8=36-32=4
√Δ=2
x1=(6-2)/2=4/2=2
x2=(6+2)/2=8/2=4
x∈(-∞,2> u<4;+∞)
licze na naj