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C₆H₅OH + 3Br₂ → C₆H₂Br₃(OH) + 3HBr
94g---------480g
x-----------0,24g
x= 0,24g*94g/480g=0,047g
liczba moli fenolu
n = 0,047g/94g/mol =0,0005 mola
cm = 0,0005mola/1dm³ = 0,0005mol/dm³
zad. 2
C₃H₇OH → Al₂O₃→ C₃H₆ + H₂O
Alkohole : propan-1-ol, propan-2-ol